asked 63.7k views
3 votes
A 10.0 L balloon contains helium gas at a pressure of 655 mmHg. What is the final pressure, in millimeters of mercury, if the final volume is 13.8 L? Please show your work in order to receive credit.

asked
User Elyase
by
7.7k points

1 Answer

5 votes

Answer:

474. 64 mm Hg

Step-by-step explanation:

  • P1 = 655 mm Hg
  • V1 = 10 L

  • P2 = ?
  • V2 = 13. 8 L

using Boyle's Law that is

P1. V1 = P2. V2

655 × 10 = P2 × 13. 8


P2 = (655 * 10)/(13.8)

P2 = 474. 64 mm Hg

answered
User Cuty
by
8.2k points
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