Question

The programming code below shows an ''if-else'' function. After the code is run, the variable ''y'' is equal to _______.

int x, y;
x = 0; y = 0;
if (x < 0) { y = y + 1; }
else { y = y + 2; }

Answer 1

2

Explanation:

Since x=0, and it's not <0, the "else statement" is executed making y=0+2

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