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(2x4−7x3−6x2+23x−12)÷(x−4)

(2x4−7x3−6x2+23x−12)÷(x−4)
asked 204k views
4 votes
(2x4−7x3−6x2+23x−12)÷(x−4)

asked
User Alexis Schad
by
8.2k points

1 Answer

6 votes

Answer:


(23x-37)/(x-4)

Explanation:

answered
User ValR
by
8.3k points
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