Question

Select the two values of x that are roots of this equation.

x² + 3x-6=0
A. X=
-3+ /33
2
B. x=-3-83
c. x. -3-15
D. x. -3*4/15
please help

Answer 1

`x1 = ( - 3 - √(33) )/(2) \\ x2 = ( - 3 + √(33) )/(2)`

Explanation:

`x = \frac{ - b + - \sqrt{ {b}^(2) - 4ac} }{2a} \\ = ( - 3 + - √(9 + 24) )/(2) \\ x1 = ( - 3 - √(33) )/(2) \\ x2 = ( - 3 + √(33) )/(2)`