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What is the solution to log Subscript 5 Baseline (10 x minus 1) = log Subscript 5 Baseline (9 x + 7)

What is the solution to log Subscript 5 Baseline (10 x minus 1) = log Subscript 5 Baseline (9 x + 7)
asked 109k views
1 vote
What is the solution to log Subscript 5 Baseline (10 x minus 1) = log Subscript 5 Baseline (9 x + 7)

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User HeyEdd
by
8.7k points

2 Answers

1 vote

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\sf{log_(5)}(\tt{10x-1})=\sf{log_(5)}(\tt{9x+7})\\\\10x-1=9x+7\\\\10x-9x=7+1\\\\\pmb{\green{\underline{\sf{x=\frak{8}}}}}

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answered
User BufBills
by
9.0k points
5 votes

Answer:

  • x = 8

Explanation:

Given:

  • log₅ (10x - 1) = log₅ (9x + 7)
  • 10x - 1 = 9x + 7
  • 10x - 9x = 7 + 1
  • x = 8
answered
User Mansa
by
8.3k points
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