Question

PLEASE HELP ME WITH THIS ONE QUESTION

What is the rest energy of a proton? (c = 2.9979 x 10^9 m/s, mp = 1.6726 x 10^-27)

Answer 1

`E_0=1.5033×10^(-10)\:\text{J}`

Step-by-step explanation:

The rest energy
`E_0` of a proton of mass
`m_p` is given by

`E_0 = m_pc^2`

`\:\:\:\:\:\:\:=(1.6726×10^(-27)\:\text{kg})(2.9979×10^8\:\text{m/s})^2`

`\:\:\:\:\:\:\:=1.5033×10^(-10)\:\text{J}`