Question

Code a program that will go through all the numbers from 1 to 100 and print them. However, if the number is evenly divisible by 3 then print the word "fizz" instead of the number. If the number is evenly divisible by 5 then print the word "buzz" instead of the number. And, if the number is evenly divisible by both 3 and 5, print the word "fizz buzz" instead of the number. Use a loop, and use modulus division. Only the driver class is needed, and in main just call 1 method called fizzBuzz().

In java.

Answer 1

public class Main

{

// required method

public static void fizzBuzz(){

// looping through 1 to 100

for(int i = 1; i <= 100; i++){

//if number is evenly divisible by both 3 and 5

if(i%3 == 0 && i%5 == 0){

System.out.println("fiz buzz");

}

// if number is divisible by 3

else if (i%3 == 0){

System.out.println("fizz");

}

// if number is divisible by 5

else if (i%5 == 0){

System.out.println("buzz");

}

// if number is not divisible by both 3 and 5

else {

System.out.println(i);

}

}

}

// main method

public static void main(String[] args) {

//calling function

fizzBuzz();

}

}

Step-by-step explanation: