Question

Graph the image of T(

–
10,
–
7) after a rotation 270° counterclockwise around the origin.

Answer 1

`T' = (-7,10)`

Explanation:

Given

`T = (10,7)`

`r = 270^o` counterclockwise

Required

Graph of T'

The rule to this is:

`(x,y) \to (-y,x)`

So, we have:

`T(10,7) \to T' (-7,10)`

Hence:

`T' = (-7,10)`

See attachment for graph