Question

Jerry leaves home driving at 50 miles per hour. Ten minutes later, Jenny drives after him at the speed 65 miles per hour. When will she overtake him?

Answer 1

Hi there!

`\large\boxed{\approx 43.33 min}}`

Recall:

d = st, where:

d = distance

s = speed

t = time

We can set up an expression where the extra ten minutes is taken into account:

50x = 65(x - 10) <--- because J left 10 minutes after, we must subtract from the time variable, or "x".

Solve for x:

50x = 65x - 650

Subtract 65x from both sides:

-15x = -650

Divide both sides by -15:

x ≈ 130/3 or 43.33 min