Question

A wire 2.80 m in length carries a current of 5.60 A in a region where a uniform magnetic field has a magnitude of 0.300 T. Calculate the magnitude of the magnetic force on the wire assuming the following angles between the magnetic field and the current.

Answer 1

Complete question:

A wire 2.80 m in length carries a current of 5.60 A in a region where a uniform magnetic field has a magnitude of 0.300 T. Calculate the magnitude of the magnetic force on the wire assuming the following angles between the magnetic field and the current.

a) 60 ⁰

b) 90 ⁰

c) 120 ⁰

Answer:

(a) When the angle, θ = 60 ⁰, force = 4.07 N

(b) When the angle, θ = 90 ⁰, force = 4.7 N

(c) When the angle, θ = 120 ⁰, force = 4.07 N

Step-by-step explanation:

Given;

length of the wire, L = 2.8 m

current carried by the wire, I = 5.6 A

magnitude of the magnetic force, F = 0.3 T

The magnitude of the magnetic force is calculated as follows;

`F = BIl \ sin(\theta)`

(a) When the angle, θ = 60 ⁰

`F = BIl \ sin(\theta)\\\\F = 0.3 * 5.6 * 2.8 * sin(60)\\\\F = 4.07 \ N`

(b) When the angle, θ = 90 ⁰

`F = BIl \ sin(\theta)\\\\F = 0.3 * 5.6 * 2.8 * sin(90)\\\\F = 4.7 \ N`

(c) When the angle, θ = 120 ⁰

`F = BIl \ sin(\theta)\\\\F = 0.3 * 5.6 * 2.8 * sin(120)\\\\F = 4.07 \ N`