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3 votes

factories : - \\ \\ p {}^(2) + 8p - 84


asked
User Dlants
by
8.5k points

1 Answer

2 votes


\implies {\blue {\boxed {\boxed {\purple {\sf { \: (p - 6)(p + 14) }}}}}}


\large\mathfrak{{\pmb{\underline{\orange{Step-by-step\:explanation}}{\orange{:}}}}}


{p}^(2) + 8p - 84


= {p}^(2) + 14p - 6p - 84

Taking
p as common from first two terms and
6 from last two terms, we have


= p(p + 14) - 6(p + 14)

Taking the factor
(p+14) as common,


= (p - 6)(p + 14)


\large\mathfrak{{\pmb{\underline{\red{Mystique35 }}{\red{❦}}}}}

answered
User Makiko
by
8.1k points

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