Question

The angle of elevation of the top of the tower from a point on the ground is 30 degree, If the height of the tower is 40 space m e t e r s, then the distance between the tower and the point is​

Answer 1

`40\sqrt3\ m`

Explanation:

Given that,

The height of the tower, h = 40 m

The angle of elevation is 30°

We need to find the distance between the tower and the point. Let the distance is x. Using trigonometry,

`\tan(30)=(h)/(x)\\\\(1)/(\sqrt3)=(40)/(x)\\\\x=40\sqrt3\ m`

So, the distance between the tower and the point is equal to
`40\sqrt3\ m`.