Question

the perimeter of a rectangle parking lot is 322M if the width of the parking lot is 74M what is its length

Answer 1

Explanation:

Perimeter of rectangle = 2( l+b)

Ie, P = 2( L+B )

In substituting,

322 = 2( L + 74)

Ie, 322 = 2L + 148

Re - arrange

Hence,

2L = 322 - 148

2L = 174

Thus, L = 174/2

L = 87M