Question

A basketball-player scores a free-throw with probability 0.9. What is the probability that her first miss occurs on the 6th shot

Answer 1

`Pr = 0.059049`

Explanation:

Given

`p = 0.9` --- probability of scoring

Required

Probability that his first miss is his 6th shot

Let q represent the event that he did not score.

Using complement rule:

`q = 1 - p = 1 - 0.9 = 0.1`

The event that his first miss is his 6th is represented as:

p p p p p q ---- That he scoress the first 5 attempts

So, the probability is:

`Pr = p^5 * q`

`Pr = 0.9^5 * 0.1`

`Pr = 0.059049`