Question

Hi, I need help with this question. Here is the question: For which data set is the median greater than the mean?

(1) { 4,7,10,13,16} (3) {8,9,10,11,12}
(2) {8,9,10,18,19} (4) {1,2,10,11, 12}
Please give me the answer(the method used for this problem) and an explanation.

Answer 1

Set 2

Explanation:

First find the median of each set (the median being the number in the middle):

(1) { 4,7,10,13,16} = 10

(2) {8,9,10,18,19} = 10

(3) {8,9,10,11,12} = 10

(4) {1,2,10,11, 12} = 10

Then find the mean of each set (the mean being average of all the numbers, to find the average add up all the numbers and divide by the amount of numbers):

(1) { 4,7,10,13,16} = 10

(2) {8,9,10,18,19} = 12.8

(3) {8,9,10,11,12} = 10

(4) {1,2,10,11, 12} = 7.2

the answer being 12.8 since 12.8 is greater than 10

Answer 2

(4) {1,2,10,11, 12}

Answer:

Solution given:

1:

{ 4,7,10,13,16}

n=5

median={n+1)/2th term=6/2=3th term=10

mean=sum/n={ 4+7+10+13+16}/{5}=10

(2)

{8,9,10,18,19}

n=5

median={n+1)/2th term=6/2=3th term=10

mean=sum/n={8+9+10+18+19}/{5}=12.8

3) {8,9,10,11,12}

n=5

median={n+1)/2th term=6/2=3th term=10

mean=sum/n={8+9+10+11+12}/{5}=10

(4) {1,2,10,11, 12}

n=5

median={n+1)/2th term=6/2=3th term=10

mean=sum/n={1+2+10+11+13}/{5}=7.4

In above

1: mean=median

2:mean>median

3:mean=median

4:mean<median

so median is greater than mean is in 4th one.

(4) {1,2,10,11, 12}