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The distance between the complex numbers z1 = 7 – 2i and z2 = 3 - 3i is ________

asked
User Keyframe
by
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1 Answer

4 votes

Answer:

sqrt(17)

Explanation:

the distance is

|(7-2i) - (3-3i)| = |4 + i|

remember, the absolute value of a complex number is

|a+bi| = sqrt(a²+b²)

in our case

sqrt(4² + 1²) = sqrt(16+1) = sqrt(17)

answered
User Jyoti
by
8.6k points

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