Question

What is the slope of a line perpendicular to the line passing through E(-1,6) and F(-2,-10)?

Answer 1

Explanation:

E(-1,6) & F(-2,-10)

`Slope = (y_(2)-y_(1))/(x_(2)-x_(1))\\\\\ \ \ \ = (-10-6)/(-2-[-1])\\`

`=(-10-6)/(-2+1)\\\\=(-16)/(-1)\\\\= 16`

Slope of the line perpendicular to this line = -1/m = -1/16