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A production machine that consists of three components connected in series. The first component follows Weibull probability distribution with shape parameter of 1.3 and scale parameter (characteristic life) of 24,000 hr. The second follows Weibull probability distribution with shape parameter of 1.9 and scale parameter (characteristic life) of 18,000 hr. The third component follows exponential distribution with MTTF= 48,000 hr. Find the reliability of the system at t = 6000

asked
User Ranamzes
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8.5k points

1 Answer

3 votes

Answer:

The correct solution is "0.66104".

Step-by-step explanation:

Given:

Component 1,


\beta=1.3


\gamma=24,000 \ hr

Component 2,


\beta = 1.9


\gamma=18,000 \ hr

Component 3,


MTTF=48,000 \ hr

Now,

At t = 6000 hr, the system reliability will be:


Rs(t=6000)=(3)/(\pi) R_1* R_2* R_3


=[e^{-((6000)/(24000) )^(1.3)}]* [e^{-((6000)/(18000) )^(1.9)}]* [e^{-((6000)/(48000) )}]


=0.66104

Thus the above is the correct solution.

answered
User LiKui
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8.2k points