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2 votes
A 4.1-kg ball is thrown from the top of a 4-m tall building (point A) with a speed of 1 m/s at an angle 2 degrees above the horizontal. If air resistance is negligible, what is the value of the kinetic energy of the ball as it hits the ground?

asked
User Benpage
by
8.5k points

1 Answer

5 votes

Answer:


K.E = 163 J

Step-by-step explanation:

From the question we are told that:

Mass
m=4.1kg

Height
h=4m

Speed
V=1m/s

Angle
\theta= 2 \textdegree

Generally the equation for K.E is mathematically given by

Since

The potential energy and kinetic energy is equal to the kinetic energy as it hits the ground.

Therefore


K.E=mgH + 0.5mV^2


K.E = (4.1)(9.81)(4) + (4.1)(1)^2*0.5


K.E = 163 J

answered
User Patrick Garner
by
8.2k points

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