Question

PLEASE HELP!!!!!!!!!!!!!

Answer 1

the answer for this is C.

Answer 2

`\text{C. }\pm (1)/(2)`

Explanation:

Start by moving the 2 to the right (so we can multiply both sides by the denominator):

`(1)/(2x^2-1)=-2`

Multiply both sides by
`2x^2-1`:

`1=-2(2x^2-1),\\1=-4x^2+2`

Move everything to one side:

`4x^2-2+1=0,\\4x^2-1=0,\\4x^2=1,\\x^2=(1)/(4),\\x=\boxed{\pm(1)/(2)}`