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Using standard reduction potentials Cr+3e = Cr -0.4 volt Cl2+2e = 2Cl +1.36 volt what the value of E for the cell with reaction 2Cr +3Cl2 = 3Cr +6Cl

Using standard reduction potentials Cr+3e = Cr -0.4 volt Cl2+2e = 2Cl +1.36 volt what the value of E for the cell with reaction 2Cr +3Cl2 = 3Cr +6Cl
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Using standard reduction potentials

Cr+3e = Cr -0.4 volt
Cl2+2e = 2Cl +1.36 volt
what the value of E for the cell with reaction
2Cr +3Cl2 = 3Cr +6Cl

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User Semra
by
7.9k points

1 Answer

6 votes

Answer:

Hindi ko Po alam sorry po

answered
User Jrosell
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7.4k points
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