Question

How many moles are equivalent to 365 g of aluminum chloride? Using the dimensions analysis. Show work

Answer 1

≈ 2.74 mol
`AlCl_(3)`

(I rounded to 3 sig figs because the starting amount has 3 sig figs.)

Step-by-step explanation:

`(365g AlCl_(3))/(1)*(1 mol AlCl_(3))/(133.34g AlCl_(3)) =` 2.73736313184 mol
`AlCl_(3)` ≈ 2.74 mol
`AlCl_(3)`

Hope this helps!