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4x2 + 3 = -7x
solve for x
x=_,_​

1 Answer

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\displaystyle\bf 4x^2+3=-7x\\4x^2+7x+3=0 \\\\D=49-48=1 \\x_1=(-7+1)/(8) =-(3)/(4) \\x_2=(-7-1)/(8) =-1\\\\Answer: \boxed{ x_1=-(3)/(4) \quad ; \quad x_2=-1}

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