Question

Sin0=12/37 find tan0

Answer 1

`\large{ \tt{❃ \: EXPLANATION}} :`

• We're provide - Sin θ =
  `(12)/(37)` which means 12 is the perpendicular & 37 is the hypotenuse [ Since Sin θ =
  `\tt{ (p)/(h)}` ] . We're asked to find out tan θ ].

`\large{ \tt{❁ \: USING \: PYTHAGORAS \: THEOREM}} :`

`\large{ \tt{❊ \: {h}^(2) = {p}^(2) + {b}^(2) }}`

`\large{ \tt{⇢ {p}^(2) + {b}^(2) = {h}^(2) }}`

`\large{ \tt{⇢ \: {b}^(2) = {h}^(2) - {p}^(2) }}`

`\large{ \tt{⇢ \: {b}^(2) = {37}^(2) - {12}^(2) }}`

`\large{ \tt{⇢ \: {b}^(2) = 1369 - 144}}`

`\large{ \tt{ ⇢{b}^(2) = 1225}}`

`\large{ \tt{⇢ \: b = √(1225)}}`

`\large{ \tt{⇢ \: b = 35 \: \text {units}}}`

• Now , We know - Tan θ=
  `\tt{ (perpendicular)/(base) }`. Just plug the values :

`\large{ \tt{➝ \: Tan \: \theta = (p)/(b) = \boxed{ \tt{ (12)/(35) }}}}`

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