Question

For f(x) = 4x+1 and g(x) = x^2 -5, find (fxg)(x)

Answer 1

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`\huge\underline{\tt{\red{Problem:}}}`

`\quad\quad\quad\quad\tt{f(x) = 4x + 1} \: and \: g(x) = {x}^(2) - 5`

`\huge\underline{\tt{\red{Fomula:}}}`

`\quad\quad\quad\quad\huge\tt{( \: f \: • \: g \: )}`

`\huge\underline{\tt{\red{Solution:}}}`

`\quad\quad\quad\quad\tt{(f \:•\: g)(x) = (4x + 1} \: ) ( {x}^(2) - 5)`

Step by step first:

`\quad\tt{ ⟶ { 4x * {x}^(2) = \boxed{4 {x}^(3)}} }`

`\quad\tt{ ⟶ { 1 * {x}^(2) = \boxed{{x}^(2)}} }`

`\quad\tt{ ⟶ { 4x * ( - 5) = \boxed{ - 20x}} }`

`\quad\tt{ ⟶ { 1 * ( - 5) = \boxed{ - 5}} }`

It will look like this:

`\quad\quad\quad\quad\tt{(f \:•\: g)(x) = (4 {x}^(3) + {x}^(2) - 20x - 5 )}`

`\huge\underline{\tt{\red{Answer:}}}`

`\quad\quad \underline{ \boxed{\tt{ \red{(f \:•\: g)(x) = 4 {x}^(3) + {x}^(2) - 20x - 5 }}}}`

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✍︎ C.Rose❀