Question

HELP!!!! if 3.50 moles of sodium hydroxide reacts with excess lead(II) nitrate, how many moles of Pb(OH)2 are produced?

Answer 1

Answer: 1.5 moles of
`Pb(OH)_2` are produced.

Step-by-step explanation:

We are given:

Moles of sodium hydroxide = 3.50 moles

The given chemical equation follows:

`Pb(NO_3)_2(aq)+2NaOH(aq)\rightarrow Pb(OH)_2(s)+2NaNO_3(aq)`

By stoichiometry of the reaction:

If 2 moles of NaOH produces 1 mole of
`Pb(OH)_2`

So, 3 moles of NaOH will produce =
`(1)/(2)* 3=1.5mol` of
`Pb(OH)_2`

Hence, 1.5 moles of
`Pb(OH)_2` are produced.