Question

Suppose that telephone calls arriving at a switchboard follow a Poisson process with an average of 5 calls per minute. What is the probability up to a minute will elapse by the time 2 calls have come into the switchboard

Answer 1

The correct answer is "0.0842".

Explanation:

Given:

X = 5

By using the Poisson's distribution formula, we get

The probability will be:

⇒
`P(x=2)=(\lambda^x.e^(-\lambda))/(x!)`

By substituting values, we get

`=((5)^2* e^(-5))/(2!)`

`=(25* e^(-5))/(2!)`

`=0.0842`