asked 191k views
4 votes
How many different codes of 6 digits are possible if the first digit must be 3, 4, 5, or 6 and if the code may not end in 0? Hint: think of positions.

asked
User ZAY
by
8.0k points

1 Answer

7 votes

Answer:

360000 possible codes

Explanation:

The first digit can only be one of four things and the last digit can't be zero.

4*10*10*10*10*9=360000

answered
User Bharti Ladumor
by
8.5k points

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