Question

Which equation has two real solutions? A. x^2-4=0 B. x-4=0 C. x^2-4=0 D. x+4=0

Answer 1

A and C (they are same equation)

x^2-4=0

x^2=4

x can be 2 and -2

2^2=4

-2^2=4

Explanation:

prove

b.

x-4=0

X=4 (one solution)

d.

x+4=0

X=-4 (one solution)