Answer:
Explanation:
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Assuming DF is a straight line,
Given E is the mid-point of DF
mCE = mGF
CE || GF
Then
mDE = mEF (E midpoint of DF)
Angle DEC = Angle EFG (corresponding angle, DF transversal of parallel lines CE and GF)
mCE = mGF (given)
Then triangles DCE and EGF are congruent by reason SAS (side-angle-side)