Question

Hi dev lol hahahahhahahahahahahahahahahahahaha

Answer 1

oh no

Explanation:

⇔⇔∈∈ω∵↑↑±±±±±±±
`\lim_(n \to \infty) a_n \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \\eq \\eq \\eq \\eq \\eq \\eq \\eq x^(2)`←⊂∈∈∈∈∈ωωωωωωωωωωωωωωωω∧∨∧∧∧∧

Answer 2

Answer: hi

Step-by-step explanation: siodrifjojseidufjsoidhfidshiufhoiersdnfiojdriofjoiedsjfpoiejdpoigheroiuhgoiutrhfbiukghvioruefdhgbiuktrhdfiougkhneoiuwhsrdtifu
`\lim_(n \to \infty) a_n \geq \alpha \leq √(x) \\ \pi \geq \lim_(n \to \infty) a_n \left \{ {{y=2} \atop {x=2}} \right. x^(2) (x)/(y) (x)/(y)`