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Solve the system of equations: y=x-3. y=x^2+2x-4

Solve the system of equations: y=x-3. y=x^2+2x-4
asked 111k views
2 votes
Solve the system of equations: y=x-3. y=x^2+2x-4

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User Santhu
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7.9k points

2 Answers

4 votes
Answer is y=x√2(x−1)
answered
User TheFitGeekGirl
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8.6k points
2 votes
Y = x - 3 ) x = y + 3
Y= x^2+2x-4 ) x = -1 + square root 5 + y
answered
User Animuson
by
8.5k points
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