Question

Can someone help me with this?

Answer 1

`hyx^(2) =bx^(2) +hx^(2)`First you get the length PX

secondly you use the sine rule a\sin A= b\sin B=c\sin C

hence hy = 30

you take 30\sin 90=18\X

cross multiply

sin 90 × 18 = 30×X

sin 90 = 1

1×18=30X

18\30=30X\30

0.6=X

then sin~1 0.6

answer 36.8699 as angle p

then get cos 36.8699