Question

Find the equation (in terms of x ) of the line through the points (-2,5) and (3,4)
y=

Answer 1

`{ \boxed{ \bf {general \: equation : y = mx + c}}} \\ m \: is \: the \: slope \\ { \green{slope = ( \triangle \: y)/( \triangle \: x) }} \\ m = ((4 - 5))/((3 - ( - 2))) \\ m = - (1)/(5) \\ \therefore \: { \red{y = - (1)/(5) x + c}} \\ consinder \: the \: first \: point : \\ 5 = ( - (1)/(5) * - 2) + c \\ c = (23)/(5) \\ \therefore \: { \boxed{ \bf{answer : 5y = - x + 23}}} \\ \\ { \underline{ \blue{ \tt{becker \: jnr}}}}`