Question

Express x^2 + 4x - 7 in the form (x + a)^2 - b where a and b are intergers

Answer 1

`x^2+4x-7=(x+4)^2-23` where
`a=4` and
`b=-23`

Explanation:

Given:
`x^2+4x-7`

Complete the square:
`(x^2+4x+16)-23`

Reduce trinomial:
`(x+4)^2-23`

Therefore,
`x^2+4x-7=(x+4)^2-23` where
`a=4` and
`b=-23`.