Question

HURRY I NEED HELP!!!!!

State the number of complex roots and the possible number of real and imaginary roots for each equation. Then find all roots, be sure to show all work!
(equations are in the image below)

Answer 1

#1

• y=x³+2x²-8x
• y=x(x²+2x-8)
• y=x(x²+4x-2x-8)
• y=x(x+4)(x-2)

roots

• -4,0,2

No complex roots

#2

• x³+2x²+2=0
• x²(x+2)=-2

2 complex roots as if we graph it only x intercept we can get rest two roots are not real .

Check the graph

Answer 2

hey mate here is ur answer:---------------------------------------------------

1) f (x) = x 3 + 2x 2 - 8x first factor of x ------> x( x^2 +2x -8) = 0 -------> x = 0 and x^2 +2x -8 = 0

1) f (x) = x 3 + 2x 2 - 8x first factor of x ------> x( x^2 +2x -8) = 0 -------> x = 0 and x^2 +2x -8 = 0 Now, you find b^2 -4ac that in this case will be = 2^2 -4*1*(-8) = 4 + 32 = 36 it means this equation has 2 different real roots and will be (-b ±√b^2 - 4ac) / 2a ------> x = 2 , -4 as result #1 has 3 real roots such as 0,2,-4

I hope this helps u

have a nice day ✌