Factor this polynomial expression. 2X2 + 12x + 18 A. 2(x+3)(x+3) B. 2(x - 3)(x-3) c. 2(x+3)(x - 3) D. (2x + 9)(x+2)

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asked Jan 28, 2022 197k views

1 Answer

Marat Mkhitaryan · Answer 1 · 2022-02-03T02:01:02+0000

$\longrightarrow{\green{A.\:2 \: ( x + 3)(x + 3) }}$

$\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}$

$2 {x}^(2) + 12x + 18$

Taking 2 as common factor, we have

$= 2 \: ( {x}^(2) + 6x + 9) \\ = 2 \: ( {x}^(2) + 3x + 3x + 9)$

Next, we take
as common from first two terms and 3 from last two terms,

$= 2 \: [x(x + 3) + 3(x + 3)]$

Taking the factor
(x+3) as common,

$= 2 \: ( x + 3)(x + 3)$

$\red{\large\qquad \qquad \underline{ \pmb{{ \mathbb{ \maltese \: \: Mystique35}}}}}$