Question

The product of two consecutive positive odd integers is 2499 find the bigger integer

Answer 1

To find the bigger integer, we need to determine the consecutive odd integers whose product is 2499. The bigger integer is 51.

Step-by-step explanation:

To find the bigger integer, we need to determine the consecutive odd integers whose product is 2499. Let's assume the first odd integer is n, and the next consecutive odd integer is (n+2). The product of these two integers can be expressed as:

n * (n+2) = 2499

Expanding the equation:

n^2 + 2n - 2499 = 0

Now we can find the values of n that satisfy this equation using factoring, completing the square, or the quadratic formula. Solving it:

n ≈ 49

Therefore, the bigger integer is (n+2) = 49+2 = 51.

Answer 2

Step-by-step explanation:

Consecutive odd integers are integers that take on the form n, n + 2, n +4, n + 6, and so on, where n is odd.

Now, Product of two consecutive positive odd integers = 2499

=>n*(n+2) = 2499

=>n^2+2^n-2499=0

=>n^2+51^n-49^n-2499=0 =>n(n+51)-49(x+51)=0

=>(n+51)(n-49)=0

=>n=49 (n is not equal to -51 which is negative integer).

So,bigger integer =(n+2)=49+2=51.