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In △ P Q R , △PQR, ∠ Q ≅ ∠ P , ∠Q≅∠P, R P = 15 RP=15 and P Q = 7 PQ=7. Find the length of Q R . QR.

asked
User Dappawit
by
7.7k points

1 Answer

2 votes

Answer:

QR = 13.3

Explanation:

We solve using Pythagoras Theorem

c² = a² + b²

RP² = PQ² + QR²

QR² = RP² - PQ²

QR = √RP² - PQ²

RP=15

PQ=7

QR = √15² - 7²

QR = √(176)

QR = 13.266499161

Approximately = 13.3

Therefore, the length of QR = 13.3

answered
User Adrian Krebs
by
8.4k points

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