Question

Using factoring what is the solution to the equation 2x^2+3x-5=0

Answer 1

Option B. ( x=1,-5/2 Or x=-5/2,1)

Step-by-step explanation:

2x2+3x−5=0

Step 1: Factor left side of equation.

(2x+5)(x−1)=0

Step 2: Set factors equal to 0.

2x+5=0 or x−1=0

x=−5/2 or x=1

(The Answer you can just switch it around but dont worry its still the same answer nothing change...)