Question

A light bulb is connected to two batteries. Each battery has 1.5V. If a student measures the current flowing through the light bulb to be 2 A, What is the resistance of the light bulb?

Answer 1

R = 0.75 ohms

Step-by-step explanation:

Given that,

The voltage of each battery, V = 1.5 V

Current through the light bulb, I = 2 A

We need to find the resistance of the light bulb. We know that,

Ohm's law, V = IR

Where

R is the resistance of the light bulb

Put all the values,

`R=(V)/(I)\\\\R=(1.5)/(2)\\\\R=0.75\ \Omega`

So, the resistance of the light bulb is equal to 0.75 ohms.