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What is the equation of the line that passes through the point (6,1) and is parallel to the line x+3y=15

asked
User KishanCS
by
8.3k points

1 Answer

3 votes

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Answer:

x + 3y = 9

Explanation:

The parallel line will have the same x- and y-coefficients. The new constant can be found by using the (x, y) values of the given point.

x + 3y = (6 +3(1)) = 9

The equation of the parallel line is ...

x + 3y = 9

answered
User Peo Bondesson
by
8.5k points

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