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In this triangle, cosA/ cosB

In this triangle, cosA/ cosB
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In this triangle, cosA/ cosB

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User Dimzak
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Answer:

So CosA/SinA = CosB/SinB = CosC/SinC or CotA = CotB = CotC. In a triangle this is possible only when A = B = C = 60 degrees. So the trianle ...

2 answers

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Top answer:

a/SinA = b/SinB = c/SinC Step-by-step explanation:

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User Tina Nyaa
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