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Explain how to determine the zeros of f(x)= (x+3)(x-2)(x-6)

1 Answer

2 votes

Answer:

The zeros of f(x) are -3, 2 , 6

Explanation:

f(x) is a polynomial of degree 3.

If the polynomial is not factorized we will either factorize to find the zero or use trial and error method.

Since the f(x) in the question is in the factorized form. we will have to equate each factor to zero.

f(x) = (x+3)(x-2)(x-6)

x + 3 = 0 => x = -3

x - 2 = 0 => x = 2

x - 6 = 0 => x = 6

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