Question

Algebra

huh still difficult and will always be.
Someone just...…..
please help me to figure out this

Answer 1

`z = 6`

Explanation:

Let's solve:

`5(z+1)=3(z+2)+11`

Step 1: Simplify both sides of the equation.

`5(z+1)=3(z+2)+11 \\ (5)(z)+(5)(1)=(3)(z)+(3)(2)+11(Distribute) \\ </p><p>5z+5=3z+6+11 \\ </p><p></p><p>5z+5=(3z)+(6+11)(Combine Like Terms) \\ </p><p>5z+5=3z+17 \\ </p><p>5z+5=3z+17`

Step 2: Subtract 3z from both sides.

`5z+5−3z=3z+17−3z \\ 2z+5=17`

Step 3: Subtract 5 from both sides.

`2z+5−5=17−5 \\ 2z=12`

Step 4: Divide both sides by 2.

`(2z)/(2) = (12)/(2) \\ z = 6`