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What is the equation of the line that is parallel to y−5=−1/3(x+2) and passes through the point (6,−1)? The equation will be in slope-intercept form.

What is the equation of the line that is parallel to y−5=−1/3(x+2) and passes through the point (6,−1)? The equation will be in slope-intercept form.
asked 121k views
5 votes
What is the equation of the line that is parallel to y−5=−1/3(x+2) and passes through the point (6,−1)?

The equation will be in slope-intercept form.

asked
User Havvg
by
7.7k points

1 Answer

7 votes

Answer:

3y-x+9=0

Explanation:

here given

the equation of line is y-5=-1/3(x+2)

or, y

answered
User Jithesh Kt
by
7.9k points
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