Question

what equation can be used to represent "six added to twice the sum of a number and four is equal to one-half of the difference of three and the number"?

Answer 1

6+2(n+4) = (3-n)÷2

Explanation:

6 + 2n + 8 = (3-n)/2

14 + 2n = (3-n)/2

multiply through by 2 to eliminate the denominator

28 + 4n = 3 - n

25 + 4n = -n

25 = -5n

n = -5