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(x+iy)^4 -(x+iy)^2 +16=0

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(x+iy)^4 -(x+iy)^2 +16=0

asked Nov 16, 2022 16.6k views

5 votes

(x+iy)^4 -(x+iy)^2 +16=0

Mathematics
college

by Ikolim

8.2k points

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1 Answer

4 votes

Answer:

below

Explanation:

that is the procedure above

(x+iy)^4 -(x+iy)^2 +16=0-example-1

Aamir Afridi answered Nov 22, 2022

by Aamir Afridi

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