In ΔIJK, the measure of ∠K=90°, KJ = 65, IK = 72, and JI = 97. What is the value of the cosine of ∠J to the nearest hundredth?

Question

asked Oct 25, 2022 37.6k views

1 Answer

Dinesh Sonachalam · Answer 1 · 2022-10-29T13:29:40+0000

Answer:

$\cos(J) = 0.67$

Explanation:

Given

$\angle K = 90^o$

KJ = 65

IK = 72

JI = 97

Required

$\cos(J)$

The question is illustrated with the attached image.

From the image, we have:

$\cos(J) = (KJ)/(JI)$

This gives:

$\cos(J) = (65)/(97)$

$\cos(J) = 0.67010309278$

$\cos(J) = 0.67$ --- approximated