Question

A lumberjack is trying to drag a small tree that he cut down. If the static

coefficient of friction of the tree on the ground is 0.5 and the tree weighs 430
N, what is the minimum amount of horizontal force that he will need to apply
so that the tree will start moving?
A. 215 N
B. 430 N
C. 365 N
D. 500 N

Answer 1

A

Step-by-step explanation:

weight of the tree =normal force

Horizontal force =coefficient of friction x Fnormal

0.5×430=215